3.273 \(\int \frac{\sqrt{1-\cos (c+d x)}}{\cos ^{\frac{5}{2}}(c+d x)} \, dx\)

Optimal. Leaf size=75 \[ \frac{2 \sin (c+d x)}{3 d \sqrt{1-\cos (c+d x)} \cos ^{\frac{3}{2}}(c+d x)}-\frac{4 \sin (c+d x)}{3 d \sqrt{1-\cos (c+d x)} \sqrt{\cos (c+d x)}} \]

[Out]

(2*Sin[c + d*x])/(3*d*Sqrt[1 - Cos[c + d*x]]*Cos[c + d*x]^(3/2)) - (4*Sin[c + d*x])/(3*d*Sqrt[1 - Cos[c + d*x]
]*Sqrt[Cos[c + d*x]])

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Rubi [A]  time = 0.0845189, antiderivative size = 75, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.08, Rules used = {2772, 2771} \[ \frac{2 \sin (c+d x)}{3 d \sqrt{1-\cos (c+d x)} \cos ^{\frac{3}{2}}(c+d x)}-\frac{4 \sin (c+d x)}{3 d \sqrt{1-\cos (c+d x)} \sqrt{\cos (c+d x)}} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[1 - Cos[c + d*x]]/Cos[c + d*x]^(5/2),x]

[Out]

(2*Sin[c + d*x])/(3*d*Sqrt[1 - Cos[c + d*x]]*Cos[c + d*x]^(3/2)) - (4*Sin[c + d*x])/(3*d*Sqrt[1 - Cos[c + d*x]
]*Sqrt[Cos[c + d*x]])

Rule 2772

Int[Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]]*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp
[((b*c - a*d)*Cos[e + f*x]*(c + d*Sin[e + f*x])^(n + 1))/(f*(n + 1)*(c^2 - d^2)*Sqrt[a + b*Sin[e + f*x]]), x]
+ Dist[((2*n + 3)*(b*c - a*d))/(2*b*(n + 1)*(c^2 - d^2)), Int[Sqrt[a + b*Sin[e + f*x]]*(c + d*Sin[e + f*x])^(n
+ 1), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] &
& LtQ[n, -1] && NeQ[2*n + 3, 0] && IntegerQ[2*n]

Rule 2771

Int[Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]]/((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(3/2), x_Symbol] :> Sim
p[(-2*b^2*Cos[e + f*x])/(f*(b*c + a*d)*Sqrt[a + b*Sin[e + f*x]]*Sqrt[c + d*Sin[e + f*x]]), x] /; FreeQ[{a, b,
c, d, e, f}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0]

Rubi steps

\begin{align*} \int \frac{\sqrt{1-\cos (c+d x)}}{\cos ^{\frac{5}{2}}(c+d x)} \, dx &=\frac{2 \sin (c+d x)}{3 d \sqrt{1-\cos (c+d x)} \cos ^{\frac{3}{2}}(c+d x)}-\frac{2}{3} \int \frac{\sqrt{1-\cos (c+d x)}}{\cos ^{\frac{3}{2}}(c+d x)} \, dx\\ &=\frac{2 \sin (c+d x)}{3 d \sqrt{1-\cos (c+d x)} \cos ^{\frac{3}{2}}(c+d x)}-\frac{4 \sin (c+d x)}{3 d \sqrt{1-\cos (c+d x)} \sqrt{\cos (c+d x)}}\\ \end{align*}

Mathematica [A]  time = 0.095005, size = 51, normalized size = 0.68 \[ -\frac{2 \sqrt{1-\cos (c+d x)} (2 \cos (c+d x)-1) \cot \left (\frac{1}{2} (c+d x)\right )}{3 d \cos ^{\frac{3}{2}}(c+d x)} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[1 - Cos[c + d*x]]/Cos[c + d*x]^(5/2),x]

[Out]

(-2*Sqrt[1 - Cos[c + d*x]]*(-1 + 2*Cos[c + d*x])*Cot[(c + d*x)/2])/(3*d*Cos[c + d*x]^(3/2))

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Maple [A]  time = 0.275, size = 55, normalized size = 0.7 \begin{align*}{\frac{\sqrt{2} \left ( 2\,\cos \left ( dx+c \right ) -1 \right ) \sin \left ( dx+c \right ) }{3\,d \left ( -1+\cos \left ( dx+c \right ) \right ) }\sqrt{2-2\,\cos \left ( dx+c \right ) } \left ( \cos \left ( dx+c \right ) \right ) ^{-{\frac{3}{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-cos(d*x+c))^(1/2)/cos(d*x+c)^(5/2),x)

[Out]

1/3/d*2^(1/2)*(2*cos(d*x+c)-1)*sin(d*x+c)*(2-2*cos(d*x+c))^(1/2)/(-1+cos(d*x+c))/cos(d*x+c)^(3/2)

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Maxima [B]  time = 1.59445, size = 221, normalized size = 2.95 \begin{align*} -\frac{2 \,{\left (\sqrt{2} - \frac{4 \, \sqrt{2} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac{3 \, \sqrt{2} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}}\right )}{\left (\frac{\sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + 1\right )}^{2}}{3 \, d{\left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}^{\frac{5}{2}}{\left (-\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}^{\frac{5}{2}}{\left (\frac{2 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac{\sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + 1\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-cos(d*x+c))^(1/2)/cos(d*x+c)^(5/2),x, algorithm="maxima")

[Out]

-2/3*(sqrt(2) - 4*sqrt(2)*sin(d*x + c)^2/(cos(d*x + c) + 1)^2 + 3*sqrt(2)*sin(d*x + c)^4/(cos(d*x + c) + 1)^4)
*(sin(d*x + c)^2/(cos(d*x + c) + 1)^2 + 1)^2/(d*(sin(d*x + c)/(cos(d*x + c) + 1) + 1)^(5/2)*(-sin(d*x + c)/(co
s(d*x + c) + 1) + 1)^(5/2)*(2*sin(d*x + c)^2/(cos(d*x + c) + 1)^2 + sin(d*x + c)^4/(cos(d*x + c) + 1)^4 + 1))

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Fricas [A]  time = 1.89588, size = 140, normalized size = 1.87 \begin{align*} -\frac{2 \,{\left (2 \, \cos \left (d x + c\right )^{2} + \cos \left (d x + c\right ) - 1\right )} \sqrt{-\cos \left (d x + c\right ) + 1}}{3 \, d \cos \left (d x + c\right )^{\frac{3}{2}} \sin \left (d x + c\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-cos(d*x+c))^(1/2)/cos(d*x+c)^(5/2),x, algorithm="fricas")

[Out]

-2/3*(2*cos(d*x + c)^2 + cos(d*x + c) - 1)*sqrt(-cos(d*x + c) + 1)/(d*cos(d*x + c)^(3/2)*sin(d*x + c))

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-cos(d*x+c))**(1/2)/cos(d*x+c)**(5/2),x)

[Out]

Timed out

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Giac [A]  time = 2.11125, size = 126, normalized size = 1.68 \begin{align*} \frac{\sqrt{2}{\left (\sqrt{2}{\left (\sqrt{2} - 2\right )} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right ) + 2 \,{\left (\sqrt{2} - \frac{3 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )} \sqrt{-\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1}}\right )} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )\right )}}{3 \, d} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-cos(d*x+c))^(1/2)/cos(d*x+c)^(5/2),x, algorithm="giac")

[Out]

1/3*sqrt(2)*(sqrt(2)*(sqrt(2) - 2)*sgn(tan(1/2*d*x + 1/2*c)) + 2*(sqrt(2) - (3*tan(1/2*d*x + 1/2*c)^2 - 1)/((t
an(1/2*d*x + 1/2*c)^2 - 1)*sqrt(-tan(1/2*d*x + 1/2*c)^2 + 1)))*sgn(tan(1/2*d*x + 1/2*c)))/d